From eaf89064f0f6abb8ebeb09c7da49cd792514c897 Mon Sep 17 00:00:00 2001
From: Mitja Felicijan <mitja.felicijan@gmail.com>
Date: Sun, 23 Sep 2018 23:30:10 +0200
Subject: content update

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+section
+  h1 Why understanding of basic math is imporant for computer programing
+  p September 21, 2018
+  a(href="https://twitter.com/mitjafelicijan") @mitjafelicijan
+
+
+
+section.center
+  q We Cannot Solve Our Problems With The Same Thinking We Used When We Created Them.
+  footer — Albert Einstein
+
+
+
+section
+  h2 How we usually find solutions and why this is problematic?
+
+  ul
+    li We search for code example instead of algorithms.
+    li We copy and paste and do testing on trial&error principle.
+    li We don't take enough time to properly understand problem we a re trying to solve.
+    li Brute force solutions we make are usually not optimized
+
+
+section
+  h3 Grid example
+  div.grid.col-1-1
+    div Lipsum
+    div Lipsum
+
+  div.grid.col-2-1
+    div Lipsum
+    div Lipsum
+
+  div.grid.col-1-2
+    div Lipsum
+    div Lipsum
+
+section
+  h2 Basic linear algebra
+
+  pre
+    code.language-css
+      | body {
+      |   background: black;
+      | }
+
+  pre
+    code.language-javascript
+      | $(document).ready(function() {
+      |   $('pre code').each(function(i, block) {
+      |     hljs.highlightBlock(block);
+      |   });
+      | });
+
+  hr
+  figcaption.right Step 1: Finding nearest point
+
+  div.center
+    img(src="drawing1.svg")
+
+  hr
+  figcaption.right Step 1: Finding nearest point
+
+  $$ \large{ \mathbb{R}^2 ∈ \vec{a} \bar{a} } $$
+  $$ \large{ e^{i\pi} + 1 = 0 } $$
+  $$ \large{ x = {-b \pm \sqrt{b^2-4ac} \over 2a} } $$
+
+  hr
+  figcaption.right Step 2: Finding nearest point
+
+  pre
+    code.language-python
+      | fruits = ["apple", "banana", "cherry"]
+      | for x in fruits:
+      |   if x == "banana":
+      |     break
+      |   print(x)
+
+  hr
+  figcaption.right Finding nearest point
+
+  $$ \large{ \mathbb{R}^2 ∈ \vec{a} \bar{a} } $$
+  $$ \large{ e^{i\pi} + 1 = 0 } $$
+  $$ \large{ x = {-b \pm \sqrt{b^2-4ac} \over 2a} } $$
+
+  hr
+  figcaption.right Finding nearest point
+
+  pre
+    code.language-c
+      | #include <stdio.h>
+      | int main () {
+      |   for( ; ; ) {
+      |       printf("This loop will run forever.\n");
+      |   }
+      |   return 0;
+      | }
+
+  hr
+  figcaption.right Finding nearest point
+
+  pre
+    code.language-python
+      | fruits = ["apple", "banana", "cherry"]
+      | for x in fruits:
+      |   if x == "banana":
+      |     break
+      |   print(x)
+
+  hr
+  figcaption.right Finding nearest point
+
+  pre
+    code.language-sql
+      | SELECT `CustomerName`, `City` FROM `Customers`;
+
+  hr
+  figcaption.right Finding nearest point
+
+  pre
+    code.language-go
+      | package main
+      | import "fmt"
+      | func main() {
+      | 	sum := 0
+      | 	for i := 0; i < 10; i++ {
+      | 		sum += i
+      | 	}
+      | 	fmt.Println(sum)
+      | }
+
+  hr
+  figcaption.right Finding nearest point
+
+  pre
+    code.language-javascript
+      | $(document).ready(function() {
+      |   $('pre code').each(function(i, block) {
+      |     hljs.highlightBlock(block);
+      |   });
+      | });
+
+  hr
+  figcaption.right Finding nearest point
+
+  pre
+    code.language-css
+      | body {
+      |   background: black;
+      | }
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